Question

Two tiny spheres carrying charges 1.8 $\mu C$ and $2.8\mu C$ are located at 40 cm apart. The potential at the mid – point of the line joining the two charges is.

• A. $3.8 \times 10^{4}V$
• B. $2.1 \times 10^{5}V$
• C. $4.3 \times 10^{4}V$
• D. $3.6 \times 10^{5}V$

Answer 1

Answer: (B)

$2.1 \times 10^{5}V$

Answer 2

: Here, $q_{1} = 1.8\mu C = 1.8 \times 10^{- 6}C,$

$q_{2} = 2.8\mu C = 2.8 \times 10^{- 6}C$

Distance between the two spheres $= 40cm = 0.4m$

For the mid – point, $r_{1} = r_{2} = \frac{0.40}{2} = 0.2m$

Potential at O,

}{= 2.1 \times 10^{5}V}$$