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Question

Physics Question on Moving charges and magnetism

Two thin long parallel wires separated by a distance b are carrying a current i ampere each. The magnitude of the force per unit length exerted by one wire on the other is

A

μ0i2b2\frac{\mu_0 i^2}{b^2}

B

μ0i22πb\frac{\mu_0 i^2}{2\pi b}

C

μ0i2πb\frac{\mu_0 i}{2\pi b}

D

μ0i2πb2\frac{\mu_0 i}{2\pi b^2}

Answer

μ0i22πb\frac{\mu_0 i^2}{2\pi b}

Explanation

Solution

Force per unit length between two wires carrying currents i1i_1 and i2i_2 at distance r is given by
\hspace10mm \frac{F}{l}=\frac{\mu_0}{2\pi}\frac{i_1i_2}{r}
Here,\hspace10mm i_1=i_2=i\, \, \, \, and\, \, \, \, r=b
\therefore\hspace15mm \frac{F}{l}=\frac{\mu_0i_2}{2\pi b}
\therefore Correct option is (b).