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Physics Question on electrostatic potential and capacitance

Two thin dielectric slabs of dielectric constants K1 and K2 (K1 < K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field 'E' between the plates with distance 'd' as measured from plate P is correctly shown by:
Two thin dielectric slabs of dielectric constants K1 and K2

A

Two thin dielectric slabs of dielectric constants K1 and K2

B

Two thin dielectric slabs of dielectric constants K1 and K2

C

Two thin dielectric slabs of dielectric constants K1 and K2

D

Two thin dielectric slabs of dielectric constants K1 and K2

Answer

Two thin dielectric slabs of dielectric constants K1 and K2

Explanation

Solution

The correct option (B): Two thin dielectric slabs of dielectric constants K1 and K2