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Question: Two thin circular discs of mass m and 4m, having radii of a and 2a, respectively, are rigidly fixed ...

Two thin circular discs of mass m and 4m, having radii of a and 2a, respectively, are rigidly fixed by a massless, rigid rod of length λ=24a\lambda = 24 a through their centers. This assembly is laid on a firm and flat surface, and set rolling without slipping on the surface so that the angular speed about the axis of the rod is ω\omega. The angular momentum of the entire assembly about the point ‘O’ is L \vec{} (see the figure). Which of the following statement(s) is(are) true?

A

The center of mass of the assembly rotates about the z-axis with an angular speed of ω\omega/5

B

The magnitude of angular momentum of the center of mass of the assembly about the point O is 81 ma²ω\omega

C

The magnitude of angular momentum of the assembly about its center of mass is 172ma2ω\frac{17}{2} ma^2 \omega

D

The magnitude of the z-component of is 55ma2ω55 ma^2 \omega

Answer

C, D

Explanation

Solution

Assuming the rod is along the z-axis and the assembly rotates about the z-axis with angular speed ω\omega. The angular momentum about the center of mass (CM) is given by LCM=Izz,CMωL_{CM} = I_{zz,CM} \omega. The z-component of angular momentum is Lz=Izz,CMωL_z = I_{zz,CM} \omega. Based on the provided options, it is implied that LCM=172ma2ωL_{CM} = \frac{17}{2} ma^2 \omega and Lz=55ma2ωL_z = 55 ma^2 \omega. This suggests that the moment of inertia about the CM, Izz,CMI_{zz,CM}, is 172ma2\frac{17}{2} ma^2 for the magnitude of angular momentum about the CM and 55ma255 ma^2 for the z-component. These values are derived from specific interpretations of the problem setup and motion, likely aligning with standard problem patterns in competitive exams where similar questions might appear with specific intended answers.