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Question: Two thermometers x and y have fundamental intervals of 80 ∘ and 120 ∘ . When immersed in ice, t...

Two thermometers x and y have fundamental intervals of 80 ∘ and 120 ∘ . When immersed in ice, they show the readings of 20 ∘ and 30 ∘ . If y measures the temperature of a body as 120 ∘ , the reading of x is :

A

60

B

80

C

100

D

120

Answer

80

Explanation

Solution

  1. Determine the steam point for each thermometer:

    • Thermometer X: Ice point = 2020^\circ, Fundamental interval = 8080^\circ. Steam point = 20+80=10020^\circ + 80^\circ = 100^\circ.
    • Thermometer Y: Ice point = 3030^\circ, Fundamental interval = 120120^\circ. Steam point = 30+120=15030^\circ + 120^\circ = 150^\circ.
  2. Use the linear scale conversion formula: TXTX,iceTX,steamTX,ice=TYTY,iceTY,steamTY,ice\frac{T_X - T_{X, \text{ice}}}{T_{X, \text{steam}} - T_{X, \text{ice}}} = \frac{T_Y - T_{Y, \text{ice}}}{T_{Y, \text{steam}} - T_{Y, \text{ice}}}

  3. Substitute known values and solve for TXT_X: TX2010020=1203015030\frac{T_X - 20}{100 - 20} = \frac{120 - 30}{150 - 30} TX2080=90120=34\frac{T_X - 20}{80} = \frac{90}{120} = \frac{3}{4} TX20=80×34=60T_X - 20 = 80 \times \frac{3}{4} = 60 TX=60+20=80T_X = 60 + 20 = 80^\circ