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Question

Question: Two temperature scales A and B are related by \(\dfrac{{A - 42}}{{110}} = \dfrac{{B - 72}}{{220.}}\)...

Two temperature scales A and B are related by A42110=B72220.\dfrac{{A - 42}}{{110}} = \dfrac{{B - 72}}{{220.}}. At which temperature two scales have the same reading?
A) 42- 42^\circ
B) 72- 72^\circ
C) +12+ 12^\circ
D) 40- 40^\circ

Explanation

Solution

Two temperatures, namely A and B, should have the same reading, so it means temperature A and temperature B have the same value. We can use this result in the above relation given in the question.

Complete step by step answer:
Since both the temperatures have the same reading, therefore we can use the result A=BA = B.
Using given relation in question, A42110=B72220.\dfrac{{A - 42}}{{110}} = \dfrac{{B - 72}}{{220.}}
Putting value of B as A in above relation (because, A=BA = B )
A42110=A72220\dfrac{{A - 42}}{{110}} = \dfrac{{A - 72}}{{220}}
On further solving, we get,
2×(A42)=A722 \times \left( {A - 42} \right) = A - 72
On solving this, we get,
2AA=84722A - A = 84^\circ - 72^\circ
On further solving, we get,
A=+12A = + 12^\circ
So, we get our answer as A=+12A = + 12^\circ .
So option (C) is correct.

Note: Since we got A=+12A = + 12^\circ , it means the two temperature scales, named as A and B which are related by the given relation in question will give the same reading whenever we will get A and B both as positive 1212 degrees.