Question
Mathematics Question on Linear Programmig Problem
Two tailors A and B earn ₹150 and ₹200 per day respectively. A can stitch 6 shirts and 4 pants per day, while B can stitch 10 shirts and 4 pants per day. If the tailors A and B work for x and y days respectively. To maximize the earning for producing at least 60 shirts and 32 pants, the LPP is:
Maximize Z = 150x + 200y, subject to 6x + 10y ≥ 60, 4x + 4y ≥ 32, x, y ≥ 0
Maximize Z = 150x + 200y, subject to 6x + 10y ≤ 60, 4x + 4y ≤ 32, x, y ≥ 0
Maximize Z = 150x + 200y, subject to 6x + 4y ≥ 60, 10x + 4y ≥ 32, x, y ≥ 0
Maximize Z = 150x + 200y, subject to 6x + 10y ≥ 60, 4x + 4y ≤ 32, x, y ≥ 0
Maximize Z = 150x + 200y, subject to 6x + 10y ≥ 60, 4x + 4y ≥ 32, x, y ≥ 0
Solution
The correct option is (A): Maximize Z = 150x + 200y, subject to 6x + 10y ≥ 60, 4x + 4y ≥ 32, x, y ≥ 0