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Question

Mathematics Question on Linear Programmig Problem

Two tailors A and B earn ₹150 and ₹200 per day respectively. A can stitch 6 shirts and 4 pants per day, while B can stitch 10 shirts and 4 pants per day. If the tailors A and B work for x and y days respectively. To maximize the earning for producing at least 60 shirts and 32 pants, the LPP is:

A

Maximize Z = 150x + 200y, subject to 6x + 10y \geq 60, 4x + 4y \geq 32, x, y \geq 0

B

Maximize Z = 150x + 200y, subject to 6x + 10y \leq 60, 4x + 4y \leq 32, x, y \geq 0

C

Maximize Z = 150x + 200y, subject to 6x + 4y \geq 60, 10x + 4y \geq 32, x, y \geq 0

D

Maximize Z = 150x + 200y, subject to 6x + 10y \geq 60, 4x + 4y \leq 32, x, y \geq 0

Answer

Maximize Z = 150x + 200y, subject to 6x + 10y \geq 60, 4x + 4y \geq 32, x, y \geq 0

Explanation

Solution

The correct option is (A): Maximize Z = 150x + 200y, subject to 6x + 10y \geq 60, 4x + 4y \geq 32, x, y \geq 0