Question

Two system of rectangular axes have the same origin. If a plane cuts the distance a, b, c from the origin then –

• A. $\frac { 1 } { a ^ { 2 } }$ + + – $\frac { 1 } { \mathrm { a } ^ { \prime 2 } }$ – – = 0
• B. $\frac { 1 } { a ^ { 2 } }$ + + + $\frac { 1 } { \mathrm { a } ^ { \prime 2 } }$ + + = 0
• C. $\frac { 1 } { a ^ { 2 } }$ + – + $\frac { 1 } { \mathrm { a } ^ { \prime 2 } }$ +– = 0
• D. $\frac { 1 } { a ^ { 2 } }$ – – + $\frac { 1 } { \mathrm { a } ^ { \prime 2 } }$ – – = 0

Answer 1

Answer: (A)

$\frac { 1 } { a ^ { 2 } }$ + + – $\frac { 1 } { \mathrm { a } ^ { \prime 2 } }$ – – = 0

Answer 2

The distance of plane + + = 1 or

+ + = 1 from origin will be same

$\left| \frac { - 1 } { \sqrt { \frac { 1 } { \mathrm { a } ^ { 2 } } + \frac { 1 } { \mathrm {~b} ^ { 2 } } + \frac { 1 } { \mathrm { c } ^ { 2 } } } } \right|$ =