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Question: Two sulphuric acid solutions are mixed as follows: \[\]\(25 \cdot 0mt\)of a \(0.50M\) Sulphuric acid...

Two sulphuric acid solutions are mixed as follows: $$$$$25 \cdot 0mtofaof a 0.50MSulphuricacidsolutionareaddedtoSulphuric acid solution are added to0 \cdot 075Lofaof a0 \cdot 25Msulphuricacidsolution.Whatisthemolarityofthemuhingmixture?(Assumevolumesareadditive)A.sulphuric acid solution. What is the molarity of the muhing mixture? (Assume volumes are additive) A.0 \cdot 501MB. B.0 \cdot 312MC. C.0 \cdot 712MD. D.0 \cdot 12M$

Explanation

Solution

The sulphuric acid which has the chemical formula as H2SO4{H_2}S{O_4} is also known as oil of vitriol. It is a mineral acid that is composed of sulphur, oxygen and hydrogen elements in it. It is colourless, odourless and viscous liquid that is soluble in water.

Formula used:
Concentration of final sulphuric acid mixture, the molarity formula,
=M1V1+M2V2Total Volume= \dfrac{{{M_1}{V_1} + {M_2}{V_2}}}{{\text{Total Volume}}}

Complete answer:
Here in the question that is given down, as we focused that is it the direct substitution into the formula, we have to look in to the values before substituting,
M1=0⋅50M{M_1} = 0 \cdot 50M
V1=251000=0⋅025L{V_1} = \dfrac{{25}}{{1000}} = 0 \cdot 025L
Here, M1{M_1} and V1{V_1} are the molarity and volume of the first sulphuric acid. Here the volume is directly converted from mili-litre to litre.
M2=0⋅25M{M_2} = 0 \cdot 25M
V2=0⋅075L{V_2} = 0 \cdot 075L
And now in order to obtain the total volume we have to add up the two volumes of the two sulphuric acid.
V=0⋅025+0⋅075=0⋅1LV = 0 \cdot 025 + 0 \cdot 075 = 0 \cdot 1L
Now coming to the main part of the question, we have our final concentration,
=M1V1+M2V2Total Volume= \dfrac{{{M_1}{V_1} + {M_2}{V_2}}}{{\text{Total Volume}}}
Now it is all the direct substitution,
=(0⋅5×0⋅025)+(0⋅25×0⋅075)0⋅1= \dfrac{{\left( {0 \cdot 5 \times 0 \cdot 025} \right) + \left( {0 \cdot 25 \times 0 \cdot 075} \right)}}{{0 \cdot 1}}
After the calculation we get our answer which then we have to look into the options to see if there is the actual solution to look into the nearer answer to them.
=0⋅3125M= 0 \cdot 3125M
After looking into the final answer we know the right option already,

Hence, the right option is (B) .

Note:
Molarity changes with the temperature because the volume changes with the temperature. So, we need to measure molarity by keeping temperature unchanged. So , in a lab when you are preparing the solution make sure to note down the temperature otherwise it will affect the calculations