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Question: Two substances A and B of equal mass m are heated at uniform rate of 6 cal s<sup>–1</sup> under simi...

Two substances A and B of equal mass m are heated at uniform rate of 6 cal s–1 under similar conditions. A graph between temperature and time is shown in figure. Ratio of heat absorbed HA / BB by them for complete fusion is-

A

94\frac{9}{4}

B

49\frac{4}{9}

C

85\frac{8}{5}

D

58\frac{5}{8}

Answer

85\frac{8}{5}

Explanation

Solution

From given curve,

Melting point for A = 600C and melting point for B = 200

Time taken by A for fusion = (6 – 2) = 4 minute

Time taken by B for fusion = (6.5 – 4) = 2.5 minute

Then HAHB\frac{H_{A}}{H_{B}}=6×4×606×2.5×60\frac{6 \times 4 \times 60}{6 \times 2.5 \times 60}=85\frac{8}{5}