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Question

Physics Question on Electromagnetic waves

Two strings with mass per unit length of 25gcm125 \, g \, cm^{-1} and 9gcm19 \, gcm^{-1} are joined together in series. The reflection coefficient for the vibration waves are

A

925\frac{9}{25}

B

35\frac{3}{5}

C

116\frac{1}{16}

D

916\frac{9}{16}

Answer

116\frac{1}{16}

Explanation

Solution

Let IrI_r and Ii I_irepresent the intensities of reflected and incident waves respectively, then
\hspace30mm \frac{I_r}{I_i} = \big(\frac{\mu - 1}{\mu + 1}\big)^2
where \hspace20mm \mu = \frac{v_1}{v_2} \, or \, v = \frac{\sqrt{\frac{T}{m_1}}}{\sqrt{\frac{T}{m_2}}} = \sqrt{\frac{m_2}{m_1}} = \sqrt{\frac{25}{9}} = \frac{5}{3}

\therefore \hspace20mm \frac{I_r}{I_i} = \Bigg [\frac{\big(\frac{5}{3}\big) - 1}{\big(\frac{5}{3}\big) + 1}\Bigg ]^2 = \frac{1}{16}