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Question: Two strings of copper are stretched to the same tension. If their cross-section area are in the rati...

Two strings of copper are stretched to the same tension. If their cross-section area are in the ratio 1 : 4, then the respective wave velocities will be –

A

4 : 1

B

2 : 1

C

1 : 2

D

1 : 4

Answer

2 : 1

Explanation

Solution

v = Tμ\sqrt{\frac{T}{\mu}}= TρA\sqrt{\frac{T}{\rho A}}

where, r = density

A = Area of cross-section

m = rA = mass of unit length