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Question

Physics Question on Waves

Two strings AA and BB of same material are stretched by same tension. The radius of the string AA is double the radius of string BB. Transverse wave travels on string AA with speed ?VAV_A? and on string BB with speed ?VBV_B?. The ratio VAVB\frac{V_{A}}{V_{B}} is

A

14\frac{1}{4}

B

12\frac{1}{2}

C

22

D

44

Answer

12\frac{1}{2}

Explanation

Solution

Velocity of a transverse wave in a stretched string v=Tμv =\sqrt{\frac{ T }{\mu}}
where TT is the tension of the string and μ\mu is mass per unit length of the string.
μ=πr2×ρ\mu=\pi r^{2} \times \rho
where rr is the radius or the string and ρ\rho is the density of the material of the string.
v=1rTπρ\therefore v =\frac{1}{ r } \sqrt{\frac{ T }{\pi \rho}}
Since T,ρT , \rho are constant
v1r\therefore v \propto \frac{1}{ r }
vAvB=rBrA\frac{ v _{ A }}{ v _{ B }}=\frac{ r _{ B }}{ r _{ A }}
=(rB2rB)=12=\left(\frac{ r _{ B }}{2 r _{ B }}\right)=\frac{1}{2}