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Question: Two straight long conductors AOB and COD are perpendicular to each other and carry currents I<sub>1<...

Two straight long conductors AOB and COD are perpendicular to each other and carry currents I1and I2. The magnitude of the magnetic induction at a point P at a distance d from the point O in a direction perpendicular to the plane ABCD is –

A

μ02πd\frac { \mu _ { 0 } } { 2 \pi d } (I1 + I­2)

B

μ04πd\frac { \mu _ { 0 } } { 4 \pi d } (I1 – I2)

C

μ02πd\frac { \mu _ { 0 } } { 2 \pi d }

D

μ02πd\frac { \mu _ { 0 } } { 2 \pi d }

Answer

μ02πd\frac { \mu _ { 0 } } { 2 \pi d }

Explanation

Solution

At P there are two fields

(1) B1 = due to AOB = μ0i12πd\frac { \mu _ { 0 } \mathrm { i } _ { 1 } } { 2 \pi \mathrm { d } } (+ y)

(2) B2 = due to COD = (– x)

\ B = B12+B22\sqrt { \mathrm { B } _ { 1 } ^ { 2 } + \mathrm { B } _ { 2 } ^ { 2 } }