Question

Two stones are projected with the same magnitude of velocity, but making different angles with horizontal. The angle of projection of one is π/3 and its maximum height is Y, the maximum height attained by the other stone with as π/6 angle of projection is

• A. Y
• B. 2 Y
• C. 3 Y
• D. $\frac{Y}{3}$

Answer 1

Answer: (D)

$\frac{Y}{3}$

Answer 2

When two stones are projected with same velocity then for complementary angles $\theta$and (90^o –$\theta$)

Ratio of maximum heights : $\frac{H_{1}}{H_{2}} = \tan^{2}\theta = \tan^{2}\frac{\pi}{3} = 3$

⇒ $H_{2} = \frac{H_{1}}{3} = \frac{Y}{3}$