Solveeit Logo

Question

Physics Question on Waves

Two stationary sources each emitting waves of wave length λλ. An observer moves from one source to other with velocity uu. Then number of beats heard by him:

A

2uλ\frac{2u}{λ}

B

υλ\frac υλ

C

uλ\sqrt {uλ}

D

υ2λ\frac {υ}{2λ}

Answer

2uλ\frac{2u}{λ}

Explanation

Solution

Two stationary sources each emitting waves

For first sourceFor \ first \ source

n1=n(vuv)=(1uv)nn_1=n(\frac {v-u}{v})=(1-\frac {u}{v})n

For second sourceFor \ second\ source

n2=n(v+uv)=(1+uv)nn_2=n(\frac {v+u}{v})=(1+\frac {u}{v})n

Beat freq.=n1n2Beat\ freq.=|n_1-n_2|

Beat freq.Beat\ freq. == n+nuvn+nuvn+\frac {nu}{v}-n+\frac {nu}{v}

Beat freq.Beat\ freq. =$$\frac {2nu}{v}

Beat freq.Beat\ freq. == 2uλ\frac {2u}{λ } [v=nλ, 1λ=nv][∵v=nλ, \ ∴\frac 1λ=\frac {n}{v}]

So, the correct option is (A): 2uλ\frac{2u}{λ}