Question
Physics Question on Waves
Two stationary sources each emitting waves of wave length λ. An observer moves from one source to other with velocity u. Then number of beats heard by him:
A
λ2u
B
λυ
C
uλ
D
2λυ
Answer
λ2u
Explanation
Solution
For first source
n1=n(vv−u)=(1−vu)n
For second source
n2=n(vv+u)=(1+vu)n
Beat freq.=∣n1−n2∣
Beat freq. = n+vnu−n+vnu
Beat freq. =$$\frac {2nu}{v}
Beat freq. = λ2u [∵v=nλ, ∴λ1=vn]
So, the correct option is (A): λ2u