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Question: Two stars emit maximum radiation at wavelength 3600\(\AA\) and 4800\(\AA\) respectively. The ratio o...

Two stars emit maximum radiation at wavelength 3600A˚\AA and 4800A˚\AA respectively. The ratio of their temperatures is

A

1 : 2

B

3 : 4

C

4 : 3

D

2 : 1

Answer

4 : 3

Explanation

Solution

T1T2=λm2λm1=48003600⇒4836=43\frac { T _ { 1 } } { T _ { 2 } } = \frac { \lambda _ { m _ { 2 } } } { \lambda _ { m _ { 1 } } } = \frac { 4800 } { 3600 } \Rightarrow \frac { 48 } { 36 } = \frac { 4 } { 3 }