Question

Two springs of spring constants $1500 \mathrm {~N} / \mathrm { m }$ and respectively are stretched with the same force. They will have potential energy in the ratio

• A. 4 : 1
• B. 1 : 4
• C. 2 : 1
• D. 1 : 2

Answer 1

Answer: (C)

2 : 1

Answer 2

Potential energy of spring $U = \frac { F ^ { 2 } } { 2 k }$ ⇒ $\frac { U _ { 1 } } { U _ { 2 } } = \frac { k _ { 2 } } { k _ { 1 } }$

$= \frac { 3000 } { 1500 } = 2 : 1$ [If F = constant]