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Question

Physics Question on Oscillations

Two springs of force constants kk and 2k2k are connected to a mass as shown below. The frequency of oscillation of the mass is

A

12πkm\frac{1}{2\pi}\sqrt{\frac{k}{m}}

B

12π2km\frac{1}{2\pi}\sqrt{\frac{2k}{m}}

C

12π3km\frac{1}{2\pi}\sqrt{\frac{3k}{m}}

D

12πmk\frac{1}{2\pi}\sqrt{\frac{m}{k}}

Answer

12π3km\frac{1}{2\pi}\sqrt{\frac{3k}{m}}

Explanation

Solution

When the oscillating mass mm is at a distance xx towards right from its equilibrium position, then the spring is stretched through distance xx while the other spring is compressed through the same distance xx. Hence, restoring force exerted by each spring on mass mm is in the same direction tending to bring it in its equilibrium position. Let F1F_1 and F2F_2 be the restoring forces produced then F1kxF_1-kx \, and F2=2kx\, F_2 =-2kx Total restoring force is F=F1+F2=kx2kx=(3k)x. F=F_1+F_2 =-kx-2kx=-(3k)x. Hence, frequency n=12π3km n=\frac{1}{2\pi}\sqrt{\frac{3k}{m}}