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Question

Question: Two springs have their force constant as \(k _ { 1 }\) and \(k _ { 2 } \left( k _ { 1 } > k _ { 2 } ...

Two springs have their force constant as k1k _ { 1 } and k2(k1>k2)k _ { 2 } \left( k _ { 1 } > k _ { 2 } \right). When they are stretched by the same force

A

No work is done in case of both the springs

B

Equal work is done in case of both the springs

C

More work is done in case of second spring

D

More work is done in case of first spring

Answer

More work is done in case of second spring

Explanation

Solution

W=F22kW = \frac { F ^ { 2 } } { 2 k }

If both springs are stretched by same force then

W1kW \propto \frac { 1 } { k }

As k1>k2k _ { 1 } > k _ { 2 } therefore W1<W2W _ { 1 } < W _ { 2 } i.e. more work is done in case of second spring.