Question

Two springs have their force constant as $k_1$ and $k_2 (k_1 > k_2)$. when they are stretched by the same force

• A. no work is done in case of both the springs
• B. equal work is done in case of both the springs
• C. more work is done in case of second spring
• D. more work is done in case of first spring

Answer 1

Answer: (C)

more work is done in case of second spring

Answer 2

Since force in both springs is same: $k _{1} \,x _{1}= k _{2} \,x _{2}$ If $k _{1}> k _{2}$ then $x _{1}< x _{2}$ Work $=0.5 \,kx ^{2}$ Hence, work by second spring is greater than first