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Question: Two spherical conductors each of capacity C are charged to potential V and –V. These are then connec...

Two spherical conductors each of capacity C are charged to potential V and –V. These are then connected by means of a fine wire. The loss of energy is

A

Zero

B

12CV2\frac{1}{2}CV^{2}

C

CV2CV^{2}

D

2CV22CV^{2}

Answer

CV2CV^{2}

Explanation

Solution

: Here, loss of energy

=C1C2(V1+V2)22(C1+C2)=CC(V+V)22(C+C)=CV2= \frac{C_{1}C_{2}(V_{1} + V_{2})^{2}}{2(C_{1} + C_{2})} = \frac{CC(V + V)^{2}}{2(C + C)} = CV^{2}