Question
Question: Two spherical bodies A (radius 6 cm) and B (radius 18 cm) are at temperature \(T_1\) and \(T_2\), re...
Two spherical bodies A (radius 6 cm) and B (radius 18 cm) are at temperature T1 and T2, respectively. The maximum intensity in the emission spectrum of A is at 500 nm and in that of B is at 1500 nm. Considering them to be black bodies, what will be the ratio of the rate of total energy radiated by A to that of B?
A. 9
B. 3
C. 2
D. 4
Solution
Stefan-Boltzmann law of black body radiation has to be used to determine ratio of the energies. We can replace the temperatures by inverse of respective wavelengths as per Wien's displacement law in finding the ratios.
Formula used:
Wien's law: In the spectra of a black body, the wavelength having maximum intensity is related to absolute temperature of the black body as:
λm=Tb
where b is Wien's constant.
Stefan-Boltzmann law:
The rate of heat energy emitted by a perfect black body can be written as:
H=σT4A
where A is the surface area of the body and σ is Stefan-Boltzmann constant.
Complete answer:
Using the Stefan-Boltzmann law, we can write the ratio of rate of total energy radiated by the two spherical bodies (black bodies) as:
EBEA=σTB4ABσTA4AA.
Now, the ratios of the areas can be written as:
ABAA=4πRB24πRA2=(RBRA)2.
The radius of sphere A is given to be 6 cm the radius of sphere B is 18 cm
⟹ABAA=(RBRA)2=(31)2.
Now, we are also given the maximum intensity wavelength emitted in the spectrum of the two bodies. By Wien's displacement law, the maximum intensity wavelength is inversely proportional to the temperature. So we can write:
TBTA=λAλB=5001500=3
Now, the ratio of the energies for the two spheres now becomes:
EBEA=(λAλB)4(RBRA)2=(3)4(31)2=9
So, the correct answer is “Option A”.
Note:
The question does not clearly mention that the value of wavelength has been given to us. As we know nm stands for nanometer which is a unit of wavelength and as wavelength is a characteristic for a spectrum we must be able to guess what to do with 1500 nm and 500 nm based on this.