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Question: Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectiv...

Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectively. The ratio of the energy radiated per second by the first sphere to that by second is –

A

1 : 1

B

16 : 1

C

4 : 1

D

1 : 9

Answer

1 : 1

Explanation

Solution

P1P2\frac{P_{1}}{P_{2}} = (T1T2)4\left( \frac{T_{1}}{T_{2}} \right)^{4} × (r1r2)2\left( \frac{r_{1}}{r_{2}} \right)^{2}