Question
Question: Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectiv...
Two spheres of the same material have radii 1 m and 4 m and temperatures 4000 K and 2000 K respectively. The energy radiated per second by the first sphere is
A
Greater than that by the second
B
Less than that by the second
C
Equal in both cases
D
The information is incomplete to draw any conclusion
Answer
Equal in both cases
Explanation
Solution
The energy radiated per second E, by a body of surface area A, at temperature TK, is given by
E=eσAT4
Hence, E1=eσ4π(1)2×(4000)4
=eσπ×1024×1012Js−1And E2=eσ4π(4)2(2000)4=eσπ×1024×1012Js−1 So, E1=E2