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Question: Two spheres made of the same substance have diameters in the ratio 1:2. Their thermal capacities are...

Two spheres made of the same substance have diameters in the ratio 1:2. Their thermal capacities are in the ratio of
A) 1:2
B) 1:8
C) 1:4
D) 2:1

Explanation

Solution

In order to solve the question, we will first use the relation of thermal capacity then we will substitute the value of mass with product of volume and density so as to find the direct relation with radius so as to use the ratio given the question to find the ratio of thermal capacity

Formula used:
thermal capacity = mass × specific heat{\text{thermal capacity = mass }} \times {\text{ specific heat}}
Volume = 43π(r1)3\dfrac{4}{3}\pi {({r_1})^3}
Mass of sphere one = volume ×\timesdensity

Complete step by step answer:
In the question we are given that there are two spheres which are made up same substances and we have to find the ratio of the thermal capacities of both the spheres
Ratio of the diameters as given in question = 1:2
As both the spheres are made of same material then they will have same specific heat
To find the thermal capacity we will use the relation
thermal capacity = mass × specific heat{\text{thermal capacity = mass }} \times {\text{ specific heat}}
Thermal capacity of sphere one = C1=m1S{C_1} = {m_1}S
Mass of sphere one = volume ×\timesdensity
Volume = 43π(r1)3\dfrac{4}{3}\pi {({r_1})^3}
Substituting the value of mass in thermal capacity
C1=43π(r1)3ρS{C_1} = \dfrac{4}{3}\pi {({r_1})^3}\rho S
Thermal capacity of sphere one = C2=m2S{C_2} = {m_2}S
Mass of sphere two = volume ×\timesdensity
Volume = 43π(r2)3\dfrac{4}{3}\pi {({r_2})^3}
Substituting the value of mass in thermal capacity
C2=43π(r2)3ρS{C_2} = \dfrac{4}{3}\pi {({r_2})^3}\rho S
Thermal capacities are in ratio
C1C2=43π(r1)3ρS43π(r2)3ρS\dfrac{{{C_1}}}{{{C_2}}} = \dfrac{{\dfrac{4}{3}\pi {{({r_1})}^3}\rho S}}{{\dfrac{4}{3}\pi {{({r_2})}^3}\rho S}}
All the constants will be cancelled and we will get
C1C2=(r1)3(r2)3\dfrac{{{C_1}}}{{{C_2}}} = \dfrac{{{{({r_1})}^3}}}{{{{({r_2})}^3}}}
Now we will be substituting the ratio of radius that 1:2 in the above equation
C1C2=(1)3(2)3\dfrac{{{C_1}}}{{{C_2}}} = \dfrac{{{{(1)}^3}}}{{{{(2)}^3}}}
Opening the cube
C1C2=18\dfrac{{{C_1}}}{{{C_2}}} = \dfrac{1}{8}
Hence, the correct option is B) 1:8

Note: Many of the people will may confuse how the ratio of diameter is directly use in the answer this because as radius is half of diameter and we have been given in the ratio so both half will cut down so it doesn’t matter ratio of both radius and diameter are same in the ratio.