Question
Question: Two sources of sound S1 and S2 produce sound waves of the same frequency 660 Hz. A listener is movin...
Two sources of sound S1 and S2 produce sound waves of the same frequency 660 Hz. A listener is moving from source S1 towards S2 with constant speed u sm and he hears10 beats per second. The velocity of sound is 330secm then u is equal to:
A.10.0smB.5.5smC.15smD.2.5sm
Solution
Use the Doppler effect concept and find the value of the apparent frequencies of the two sources found by the observer and find the difference of the apparent frequencies which is equal to the number of beats heard by the observer
Complete step-by-step answer:
The observer hears a different frequency from what the source produces as explained by the doppler effect. Here we need to find the apparent frequencies of both the sources found by the person as he moves with the speed u
The apparent frequency of source 1 heard when the person is moving towards Source 2 is given by
n1=(v−vsv−vo)n where the n is the true frequency and the vo is the velocity of the observer and the vs is the velocity of the source moving.
So we get the apparent frequency of the source 1 as heard by the man is
n1=(v−vsv−vo)n=(330+0330−u)660=(330−u)(2)
The apparent frequency of source 2 heard when the person is moving towards Source 2 is given by
n1=(v−vsv−vo)n
So we get the apparent frequency of the source 2 as heard by the man is
n2=(v−vsv−vo)n=(330+0330+u)660=(330+u)(2)
Now the number of beats is the difference in the apparent frequency heard by the man
So we get that
n2−n1=10=2u+2u=4u
So we get u=410=2.5sm
Note: The most common mistake that one tends to make in the problems related to the doppler effect the sign convention to be taken for the two sources depending on the direction of the movement of the observer. The sign is negative when the observer is moving away and the sign is positive when the observer is moving towards the source.