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Question

Physics Question on beats

Two sources of sound placed close to each other, are emitting progressive waves given by y1=4sin600πty _{1}=4 \sin 600\, \pi t and y2=5sin608πt:y _{2}=5 \sin 608\, \pi t : An observer located near these two sources of sound will hear

A

4 beats per second with intensity ratio 25 : 16 between waxing and waning

B

8 beats per second with intensity ratio 25 : 16 between waxing and waning

C

8 beats per second with intensity ratio 81 : 1 between waxing and waning

D

4 beats per second with intensity ratio 81 : 1 between waxing and waning

Answer

4 beats per second with intensity ratio 81 : 1 between waxing and waning

Explanation

Solution

The correct answer is D:4 beats per second with intensity ratio 81:181\ratio 1 between waxing and waning
Comparing with y1=a1sin2πf1ty _{1}= a _{1} \sin 2 \pi f _{1} t
and y2=a2sin2πf2ty _{2}= a _{2} \sin 2 \pi f _{2} t
we get f1=300Hz,f2=304Hzf_1 =300\, Hz,\, f _{2}=304\, Hz
Number of beats =f2f1=4s1= f _{2}- f _{1}=4\, s ^{-1}
ImaxImin=(a1+a2a1a2)2\frac{ I _{\max }}{ I _{\min }}=\left(\frac{ a _{1}+ a _{2}}{ a _{1}- a _{2}}\right)^{2}
=ImaxImin=(4+545)2=811=\frac{ I _{\max }}{ I _{\min }}=\left(\frac{4+5}{4-5}\right)^{2}=\frac{81}{1}