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Question: Two solid bodies of equal masses are heated at the same rate under identical condition. The change i...

Two solid bodies of equal masses are heated at the same rate under identical condition. The change is temperature is shown graphically as a function of time. The ratio of specific heat in solid form should be (SA/SB) –

A

4/3

B

21/8

C

15/8

D

¾

Answer

21/8

Explanation

Solution

Let "P" is the rate at which heat is supplied to both A & B.

For A: P(6) = mCA (40) … (1)

For B: P(4) = mCB (70) … (2)

From (1) & (2),

64\frac{6}{4}=(40)(70)\frac{(40)}{(70)} Ž CACB\frac{C_{A}}{C_{B}}=420160\frac{420}{160}=218\frac{21}{8}