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Question: Two solid A and B are present in two different container having same volume and same temperature fol...

Two solid A and B are present in two different container having same volume and same temperature following equilibrium are established :

In container (1) A(s) D(g) + C(g) PT = 40 atm at equilibrium

In container (2) B(s) E(g) + F(g) PT = 60 atm at equilibrium

If excess of A and B are added to a third container having double the volume and at same temperature then, the total pressure of this container at equilibrium is :

A

50 atm

B

100 atm

C

200 atm

D

70 atm

Answer

50 atm

Explanation

Solution

A(s) X + Y

α+β\alpha + \beta

B(s) Y + Z

\Rightarrow

2(α+β)=50α+β=25\Rightarrow \quad 2 ( \alpha + \beta ) = 50 \quad \Rightarrow \quad \alpha + \beta = 25

250=25αα=10,β=15\Rightarrow \quad 250 = 25 \alpha \quad \Rightarrow \quad \alpha = 10 , \quad \beta = 15

=β(α+β)=15×25=375\Rightarrow \quad = \beta ( \alpha + \beta ) = 15 \times 25 = 375