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Question: Two soap bubbles of radii r<sub>1</sub> and r<sub>2</sub> equal to 4cm and 5cm are touching each oth...

Two soap bubbles of radii r1 and r2 equal to 4cm and 5cm are touching each other over a common surface S1S2S_{1}S_{2} (shown in figure). Its radius will be

A

4 cm

B

20 cm

C

5 cm

D

4.5 cm

Answer

20 cm

Explanation

Solution

Radius of curvature of common surface of double bubble r=r2r1r2r1=5×454=20cmr = \frac{r_{2}r_{1}}{r_{2} - r_{1}} = \frac{5 \times 4}{5 - 4} = 20cm