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Question: Two small spherical balls each carrying a charge *Q* = 10\(\mu C\) (10 micro-coulomb) are suspended ...

Two small spherical balls each carrying a charge Q = 10μC\mu C (10 micro-coulomb) are suspended by two insulating threads of equal lengths 1 m each, from a point fixed in the ceiling. It is found that in equilibrium threads are separated by an angle 600 between them, as shown in the figure. What is the tension in the threads. (Given : 1(4πε0)=9×109Nm/C2\frac{1}{\left( 4\pi\varepsilon_{0} \right)} = 9 \times 10^{9}Nm/C^{2})

A

8 N

B

1.8 N

C

18 N

D

None of these

Answer

1.8 N

Explanation

Solution

From the geometry of figure

r = 1m

In the condition of equilibrium Tsin30o=FeT\sin 30^{o} = F_{e}

T×12=9×109.(10×106)212T \times \frac{1}{2} = 9 \times 10^{9}.\frac{(10 \times 10^{- 6})^{2}}{1^{2}}

\RightarrowT= 1.8 N