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Question

Physics Question on coulombs law

Two small spheres each having equal positive charge QQ (Coulomb) on each are suspended by two insulating strings of equal length LL (metre) from a rigid hook (shown in figure). The whole set up is taken into satellite where there is no gravity. The two balls are now held by electrostatic forces in horizontal position, the tension in each string is then

A

Q216πε0L2\frac{Q^{2}}{16 \pi \varepsilon_{0} L^{2}}

B

Q28πε0L2\frac{Q^{2}}{8 \pi \varepsilon_{0} L^{2}}

C

Q24πε0L2\frac{Q^{2}}{4 \pi \varepsilon_{0} L^{2}}

D

Q22πε0L2\frac{Q^{2}}{2 \pi \varepsilon_{0} L^{2}}

Answer

Q216πε0L2\frac{Q^{2}}{16 \pi \varepsilon_{0} L^{2}}

Explanation

Solution

In this case, tension will be equal to force

The tension in each string
T=FT =F
=14πε0Q2(2L)2=\frac{1}{4 \pi \varepsilon_{0}} \frac{Q^{2}}{(2 L)^{2}}
=Q216πε0L2=\frac{Q^{2}}{16 \pi \varepsilon_{0} L^{2}}