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Question

Physics Question on Magnetic properties of materials

Two small magnets each of magnetic moment 10 Am2Am^2 are placed in end on position 0.1 m apart from their centres. The force acting between them is

A

0.6×107N0.6\times10^7N

B

0.06×107N0.06\times10^7N

C

0.6N0.6\,N

D

0.06N0.06 \,N

Answer

0.6N0.6\,N

Explanation

Solution

Magnetic force, F=μ04π6M1M2r4F =\frac{\mu_0}{4\pi}\frac{6M_1 M_2}{r^4}
F=107×6×10×10(0.1)4F = 10^{-7}\times\frac{6\times10\times10}{(0.1)^4}
F=600×1070.0001F=\frac{600\times10^{-7}}{0.0001}
F=0.6NF=0.6N