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Question: Two small, identical spheres having +*Q* and – *Q* charge are kept at a certain distance. *F* force ...

Two small, identical spheres having +Q and – Q charge are kept at a certain distance. F force acts between the two. If in the middle of two spheres, another similar sphere having +Q charge is kept, then it experience a force in magnitude and direction as

A

Zero having no direction

B

8F towards +Q charge

C

8F towards – Q charge

D

4F towards +Q charge

Answer

8F towards – Q charge

Explanation

Solution

Initially, force between A and C F=kQ2r2F = k\frac{Q^{2}}{r^{2}}

When a similar sphere B having charge +Q is kept at the mid point of line joining A and C, then Net force on B is

Fnet=FA+FC=kQ2(r2)2+kQ2(r2)2=8kQ2r2=8FF_{net} = F_{A} + F_{C} = k\frac{Q^{2}}{\left( \frac{r}{2} \right)^{2}} + \frac{kQ^{2}}{\left( \frac{r}{2} \right)^{2}} = 8\frac{kQ^{2}}{r^{2}} = 8F.(Direction is shown in figure)