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Question: Two small identical spheres having charges +10 mC and –90 mC attract each other with a force of F ne...

Two small identical spheres having charges +10 mC and –90 mC attract each other with a force of F newton. If they are kept in contact and then separated by the same distance, the new force between them is –

A

F/6

B

16F

C

16 F/9

D

9F

Answer

16 F/9

Explanation

Solution

F = ....(1)

After contact, change on each,

=q2q _ { 2 } ^ { \prime } = 10+(90)2\frac { 10 + ( - 90 ) } { 2 } = – 40 mC

F ' = k(40×40)r2\frac { \mathrm { k } ( 40 \times 40 ) } { \mathrm { r } ^ { 2 } } \ = 40×4010×90\frac { 40 \times 40 } { 10 \times 90 } =169\frac { 16 } { 9 } \ F¢ = 169\frac { 16 } { 9 }F