Question

Two small balls having equal positive charge Q (coulomb) on each are suspended by two insulated string of equal length L meter, from a hook fixed to a stand. The whole set up is taken in satellite into space where there is no gravity (state of weight less ness). Then the angle between the string and tension in the string is

• A. $180^{o},\frac{1}{4\pi\varepsilon_{0}}.\frac{Q^{2}}{(2L)^{2}}$
• B. $90^{\circ},\frac{1}{4\pi\varepsilon_{0}}.\frac{Q^{2}}{L^{2}}$
• C. $180^{\circ},\frac{1}{4\pi\varepsilon_{0}}.\frac{Q^{2}}{2L^{2}}$
• D. $180^{o},\frac{1}{4\pi\varepsilon_{0}}.\frac{QL}{4L^{2}}$

Answer 1

Answer: (A)

$180^{o},\frac{1}{4\pi\varepsilon_{0}}.\frac{Q^{2}}{(2L)^{2}}$

Answer 2

In case to weightlessness following situation arises So angle $\theta = 180^{\circ}$ and force $F = \frac{1}{4\pi t_{0}}.\frac{Q^{2}}{(2L)^{2}}$