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Question: Two slits in young’s double slit experiment have widths in the ratio 81: 1. The ratio of the amplitu...

Two slits in young’s double slit experiment have widths in the ratio 81: 1. The ratio of the amplitudes of light waves is :

A

3:1

B

3:2

C

9:1

D

6:1

Answer

9:1

Explanation

Solution

: Width ratio, β1β2=I1I2=811\frac{\beta_{1}}{\beta_{2}} = \frac{I_{1}}{I_{2}} = \frac{81}{1}

\thereforeAmplitude ratio,

A1A2=I1I2=811=9:1\frac{A_{1}}{A_{2}} = \sqrt{\frac{I_{1}}{I_{2}}} = \sqrt{\frac{81}{1}} = 9:1