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Question: Two slits are made one millimeter apart and the screen is placed one metre away. The frings separati...

Two slits are made one millimeter apart and the screen is placed one metre away. The frings separation when blue green light of wavelength 500 nm is used is:

A

5×10−4m5 \times 10^{- 4}m

B

2.5×10−3m2.5 \times 10^{- 3}m

C

2×10−4m2 \times 10^{- 4}m

D

10×10−4m10 \times 10^{- 4}m

Answer

5×10−4m5 \times 10^{- 4}m

Explanation

Solution

: Fringe width, β=Dλd\beta = \frac{D\lambda}{d}

Here, D = 1 m and d= 1×10−3m1 \times 10^{- 3}m

}{\therefore\beta = \frac{1 \times 5 \times 10^{- 7}}{1 \times 10^{- 3}} = 5 \times 10^{- 4}m = 0.5mm}$$