Solveeit Logo

Question

Physics Question on Wave optics

Two slits 4mm4\, mm apart, are illuminated by light of wavelength 6000?6000\, ?. What will be the fringe width on a screen placed 2m2\, m from the slits?

A

0.12 mm

B

0.3 mm

C

3.0 mm

D

4.0 mm

Answer

0.3 mm

Explanation

Solution

Separation of slits d=4mm=4×103md=4\, mm =4 \times 10^{-3} m Wavelength λ=6000?=6×107m\lambda=6000\, ?=6 \times 10^{-7} m Distance of screen D=2mD=2\, m Fringe width β=λDd\beta =\frac{\lambda D}{d} =6×107×24×103=\frac{6 \times 10^{-7} \times 2}{4 \times 10^{-3}} =3×104m=3 \times 10^{-4} m =0.3mm=0.3\, mm