Question

Two similar coils of radius $R$ are lying concentrically with their planes at right angles to each other. The currents flowing in them are $I$ and $2I$, respectively. The resultant magnetic field induction at the centre will be

• A. $\frac{\sqrt5 \mu_0 I}{2R}$
• B. $\frac{\sqrt \mu_0 I}{2R}$
• C. $\frac{\mu_0 I}{2R}$
• D. $\frac{\mu_0 I}{R}$

Answer 1

Answer: (A)

$\frac{\sqrt5 \mu_0 I}{2R}$

Answer 2

Magnetic field induction due to vertical loop at the centre O is
$B_{1}=\frac{\mu_{0} I}{2 R}$ It acts in horizontal direction.
Magnetic field induction due to horizontal loop at the centre O is
$B_{2}=\frac{\mu_{0} 2 I}{2 R}$
It acts in vertically upward direction.
As $B_{1}$ and $B_{2}$ are perpendicular to each other, therefore the resultant magnetic field induction at the centre $O$ is
$B_{n e t}=\sqrt{B_{1}^{2}+B_{2}^{2}}=\sqrt{\left(\frac{\mu_{0} I}{2 R}\right)^{2}+\left(\frac{\mu_{0} 2 I}{2 R}\right)^{2}} B_{n e t}=\frac{\mu_{0} I}{2 R} \sqrt{(1)^{2}+(2)^{2}}$
$=\frac{\sqrt{5} \mu_{0} I}{2 R}$