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Question: Two similar coils of radius \( R \) are lying concentrically with their planes at right angles to ea...

Two similar coils of radius RR are lying concentrically with their planes at right angles to each other. The currents flowing in them are II and 2I2I respectively. The resultant magnetic field induction at the center will be:
(A) μ0I2R\dfrac{{{\mu _0}I}}{{2R}}
(B) μ0IR\dfrac{{{\mu _0}I}}{R}
(C) 5μ0I2R\dfrac{{\sqrt 5 {\mu _0}I}}{{2R}}
(D) 3μ0I2R\dfrac{{3{\mu _0}I}}{{2R}}

Explanation

Solution

Hint : Here, the magnetic field is the area around a magnet in which there is magnetic force. The moving electric charges can make magnetic fields. Two coils of radius RR are concentric with their planes at right angles to each other and we have to calculate the resultant magnetic field induction at the center by using formula of magnetic field at the center of the coil given by:
B=μ0nI2aB = \dfrac{{{\mu _0}nI}}{{2a}} ; The nn is the no. of turns of the coil, II is the current and aa is the radius of the coil.
Using this formula we have to find the resultant magnetic field induction.

Complete Step By Step Answer:
Here, we have been given the two coils perpendicular to each other as shown in figure below:

From the figure we have to draw the magnetic field at the center of the coil with magnetic field B1{B_1}
B1{B_1} is to be calculated by the magnetic field induction formula B=μ0nI2aB = \dfrac{{{\mu _0}nI}}{{2a}}
Therefore,
B1=μ0I2R{B_1} = \dfrac{{{\mu _0}I}}{{2R}} ......…. (Number of turns is n=1n = 1 ) (1)(1)
Magnetic field at center due to second coil perpendicular to the first coil is given by B2{B_2}
B2=μ0(2I)2R{B_2} = \dfrac{{{\mu _0}\left( {2I} \right)}}{{2R}} …. (2)(2)
Hence, from (1)(1) and (2)(2) , we get
The net magnetic field at the center =B12+B22= \sqrt {{B_1}^2 + {B_2}^2}
=5μ0I2R= \dfrac{{\sqrt 5 {\mu _0}I}}{{2R}}
Thus, the resultant magnetic field induction is calculated as 5μ0I2R\dfrac{{\sqrt 5 {\mu _0}I}}{{2R}}
The correct answer is option C.

Note :
The resultant magnetic field induction at center is obtained by the formula we have used above. This formula is for nn no. of turns of the coil but here we know here that the coil is of one turn only. The net magnetic field is calculated as the square root of the sum of the squares of magnetic fields of two coils.