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Question

Physics Question on Magnetic properties of materials

Two short bar magnets with pole strengths of 900 ab-amp ×\times cm and 100 ab-amp ×\times cm are placed with their axes in the same vertical lines with similar poles facing each other. Each magnet has length of 1 cm. When the separation between the nearer poles is 1 cm. The weight of the.upper .magnet is supported by the repulsive force between the magnets. If g is 1000 cm/sec2cm/sec^2 the mass of the upper magnet is:

A

100g

B

45g

C

77.5g

D

55g

Answer

55g

Explanation

Solution

In equilibrium position net repulsion due to magnetic interaction = weight of the upper megnet 900×10012+(900)×(100)32+900(100)22+(900)10022+=m×1000m=55g\frac{900 \times 100}{1^2} + \frac{(-900) \times (-100)}{3^2} + \frac{900(-100)}{2^2} + \frac{(-900) 100}{2^2} + = m \times 1000 \, m = 55 \, g