Solveeit Logo

Question

Physics Question on Magnetic properties of materials

Two short bar magnets P and Q are arranged such that their centres are on the X-axis and are separated by a large distance. The magnetic axes of P and Q are along X and Y axes respectively. At a point R, midway between their centres, if B is the magnitude of induction due to Q, the magnitude of total induction at R due to the both magnets is:

A

3B

B

5\sqrt{5} B

C

52\frac{\sqrt{5}}{2} B

D

B

Answer

5\sqrt{5} B

Explanation

Solution

The point R will be in end-on position with respect to one dipole and in broad-side on position with respect to the other.So, BP=μ04π2M1r13{{B}_{P}}=\frac{{{\mu }_{0}}}{4\pi }\frac{2{{M}_{1}}}{r_{1}^{3}} and BQ=μ04πM2r23{{B}_{Q}}=\frac{{{\mu }_{0}}}{4\pi }\frac{{{M}_{2}}}{r_{2}^{3}} Since, M1=M2=M,r1=r2=r{{M}_{1}}={{M}_{2}}=M,\,\,{{r}_{1}}={{r}_{2}}=r and BQ=B{{B}_{Q}}=B \therefore BP=2B{{B}_{P}}=2B However, as BP{{B}_{P}} and BQ{{B}_{Q}} are perpendicular to each other, B=BP2+BQ2B=\sqrt{B_{P}^{2}+B_{Q}^{2}} =(2B)2+B2=\sqrt{{{(2B)}^{2}}+{{B}^{2}}} =5B2=\sqrt{5{{B}^{2}}} =5B=\sqrt{5B}