Solveeit Logo

Question

Physics Question on Magnetic properties of materials

Two short bar magnets of magnetic moments mm each are arranged at the opposite corners of a square of side d such that their centres coincide with the corners and their axes are parallel. If the like poles are in the same direction, the magnetic induction at any of the other corners of the square is

A

μ04πmd3 \frac{\mu_{0}}{4\pi} \frac{m}{d^{3}}

B

μ04π2md3 \frac{\mu_{0}}{4\pi} \frac{2m}{d^{3}}

C

μ04πm2d3 \frac{\mu_{0}}{4\pi} \frac{m}{2d^{3}}

D

μ04πm32d3 \frac{\mu_{0}}{4\pi} \frac{m^3}{2d^{3}}

Answer

μ04πmd3 \frac{\mu_{0}}{4\pi} \frac{m}{d^{3}}

Explanation

Solution

Magnetic induction at point EE due to magnet at FF (axial point) is B1=μ04π2md3B_{1} = \frac{\mu_{0}}{4\pi} \frac{2m}{d^{3}} It acts along EFEF. Magnetic induction at point EE due to magnet at DD (equatorial point) is B2=μ04πmd3B_{2} = \frac{\mu_{0}}{4\pi} \frac{m}{d^{3}} It acts along FEFE. Resultant magnetic induction at point EE is B=B1B2=μ0m4πd3B = B_{1} - B_{2} = \frac{\mu_{0}m}{4\pi d^{3}}