Question

Two SHM are represented by y₁ = 0.1 sin (100πt + π/3) and y₂ = 0.1 cosπt. The phase difference of the velocity of particle 1 with respect to the particle 2 is

• A. – π/6
• B. π/3
• C. –π/3
• D. +π/6

Answer 1

Answer: (A)

– π/6

Answer 2

$\varphi = \frac{\pi}{3} - \frac{\pi}{2} = \frac{- \pi}{6}$.

Q cos πt = sin$\left( \frac{\pi}{2} + \pi t \right)$