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Question: Two SHM are given by y<sub>1</sub> = a sin [(π/2)t + Q] and y<sub>2</sub> = b sin [2πt/3 + Q]. The p...

Two SHM are given by y1 = a sin [(π/2)t + Q] and y2 = b sin [2πt/3 + Q]. The phase difference between these after 1 sec. is

A

π

B

π/2

C

π/4

D

π/6

Answer

π/6

Explanation

Solution

t = 1 sec. y1 = a sin (π/2 + Q)& y2 = b sin (2π/3 + Q) phase difference is (2π3+Q)\left( \frac{2\pi}{3} + Q \right) - (π/2 + Q) = π/6 Hence Answer is (4)