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Question

Chemistry Question on Gas laws

Two separate bulbs contain gas A and gas B. The density of gas A is twice as that of B. The molecular mass of A is half as that of B. If temperature is constant, the ratio of the pressure of A and B is

A

1:01

B

1:02

C

4:01

D

2:01

Answer

4:01

Explanation

Solution

d=PMRTd=\frac{PM}{RT} Given : dAdB=2,MAMB=12\frac{d_{A}}{d_{B}}=2,\, \frac{M_{A}}{M_{B}}=\frac{1}{2} dAdB=PAMART×RTPBMB=2PAPB×MAMB=2\frac{d_{A}}{d_{B}}=\frac{P_{A}M_{A}}{RT}\times\frac{RT}{P_{B}M_{B}}=2\,\,\Rightarrow\,\, \frac{P_{A}}{P_{B}}\times\frac{M_{A}}{M_{B}}=2 PAPB×12=2PAPB=4:1\Rightarrow\,\, \frac{P_{A}}{P_{B}}\times\frac{1}{2}=2\,\,\Rightarrow\,\, \frac{P_{A}}{P_{B}}=4:1