Question
Question: Two satellites \({{\text{S}}_{\text{1}}}\text{ and }{{\text{S}}_{2}}\) revolve around a planet in a ...
Two satellites S1 and S2 revolve around a planet in a coplanar orbits in the same sense. The periods of revolution are 1h and 8h respectively. The radius of orbit of S1 is 104km. When S2 is closest to S1, find (a) the speed of S2 relative of S1 and (b) the angular speed of S2 as observed by an astronaut in S1?
Solution
Hint: We can find the angular velocity of an object if we know the time period of the satellite. Also, the linear velocity of both the satellites can be calculated if we know the radius of the orbit.
Complete step by step answer:
We have two satellites S1 and S2 whose time period are 1h and 8h respectively. So the angular velocity associated with a satellite whose time period is T, is given by
Angular Velocity (ω)=T2π
So the angular velocity of the satellite S1 is given by,
ω1=T12π
ω1=12π
ω1=2π rad(hr)−1
So the angular velocity of the satellite S2 is given by,
ω2=T22π
ω2=82π
ω2=0.25π rad(hr)−1
So the angular speed of S2 as seen from the astronaut in S1 is,
ω21=ω1−ω2
ω21=(2−0.25)π
ω21=1.75π rad(hr)−1
So the angular speed of S2 with respect to an astronaut in S1 is ω21=1.75π rad(hr)−1
According to Kepler's third law of planetary motion, we know that the square of time period is directly proportional to cube of the semi major axis.
T2∝a3
Here the path of rotation is considered circular. So we can equate, the ratio of square of time period of S2 and S1 to the ratio of cube of radius of the orbit of S2 and S1.
T12T22=r13r23
We can substitute the values of the time periods and the radius of S1 in order to calculate the radius of orbit of S2.
1282=(104km)3r23
r2=r1(8)32
∴r2=4×104 km
So the linear velocity of a body can be written as the product of radius and angular velocity,
v=rω
So the linear velocity of S1 is given by,
v1=r1ω1
v1=(104)(2π)
v1=2π×104 km(hr)−1
The linear velocity of S2 is given by,
v2=r2ω2
v2=(4×104)(0.25π)
v2=π×104 km(hr)−1
The speed of S2 relative to S1 is given by the difference between v2 and v1.
Relative Velocity (v21)=v1−v2
v21=(2−1)π×104
∴v21=π×104 km(hr)−1
So the relative speed of S2 to S1 is v21=π×104 km(hr)−1
Note:
Angular velocity is the measure of how fast an object rotates about a point.
Two types of angular velocities are there,
1. Orbital Angular Velocity: Velocity with which an object rotates around an object.
2. Spin Angular Velocity: Velocity with which an object rotates about its center of mass.