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Question

Physics Question on Gravitation

Two satellites AA and BB go round a planet in circular orbits having radii 4R4R and RR respectively. If the speed of AA is 3v3v, the speed of BB will be:

A

43v\frac{4}{3}v

B

3v3v

C

6v6v

D

12v12v

Answer

6v6v

Explanation

Solution

The orbital speed of a satellite is given by:
v=GMR.v = \sqrt{\frac{GM}{R}}.
For satellites AA and BB:
vAvB=RBRA=R4R=12.\frac{v_A}{v_B} = \sqrt{\frac{R_B}{R_A}} = \sqrt{\frac{R}{4R}} = \frac{1}{2}.
Thus:
vB=2vA.v_B = 2v_A.
Given vA=3vv_A = 3v, the speed of BB is:
vB=23v=6v.v_B = 2 \cdot 3v = 6v.